8x^2-49x+56=0

Solution for 8x^2-49x+56=0 equation:

8x^2-49x+56=0

a = 8; b = -49; c = +56;
Δ = b2-4ac
Δ = -492-4·8·56
Δ = 609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{609}}{2*8}=\frac{49-\sqrt{609}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{609}}{2*8}=\frac{49+\sqrt{609}}{16}
$